Quadratic Functions practice questions
Quadratic function questions are about the parabola: its vertex, axis of symmetry, intercepts, and direction. Vertex form shows the vertex directly, and factored form shows the x-intercepts.
Quadratic Functions questions
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- 1Quadratic functionsStandard
What is the vertex of y = 2(x - 3)^2 + 1?
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Answer: (3, 1)
In vertex form a(x - h)^2 + k, the vertex is (h, k). Here h = 3 and k = 1.
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What is the axis of symmetry of the parabola y = x^2 - 10x + 7?
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Answer: x = 5
The axis of symmetry of y = ax^2 + bx + c is x = -b / (2a). Here that is -(-10)/(2 × 1) = 5.
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The graph of y = (x - 2)(x + 6) crosses the x-axis at two points. What is the x-coordinate of its vertex?
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Answer: -2
The roots are x = 2 and x = -6, and a parabola is symmetric about the midpoint of its roots: (2 + (-6))/2 = -2.
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The parabola y = x^2 + bx + 7 has its vertex at x = 3. What is b?
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Answer: -6
The vertex sits at x = -b / (2a) with a = 1, so -b / 2 = 3 and b = -6.
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At which points does the graph of y = x^2 - 8x + 15 cross the x-axis?
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Answer: x = 3 and x = 5
The graph crosses where y = 0, and x^2 - 8x + 15 factors as (x - 3)(x - 5). The signs in the brackets are the opposite of the roots, which is what the second choice gets wrong.
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What is the minimum value of y = x^2 - 6x + 11?
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Answer: 2
Complete the square: y = (x - 3)^2 + 2. The squared term is never negative, so the smallest value of y is 2, reached at x = 3.
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The parabola y = -(x - 5)^2 + 12 has which of the following?
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Answer: A maximum of 12 at x = 5
The negative sign in front of the squared term opens the parabola downward, so the vertex is a maximum. Vertex form gives the vertex at (5, 12).
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The graph of y = x^2 + kx + 16 touches the x-axis at exactly one point. What are the possible values of k?
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Answer: 8 and -8
One touching point means the discriminant is zero: k^2 - 64 = 0, so k = 8 or k = -8. Reporting only the positive value answers half the question.
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What is the minimum value of f(x) = x^2 - 6x + 11?
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Answer: 2
Completing the square gives f(x) = (x - 3)^2 + 2. A square is never negative, so the smallest value is 2, reached at x = 3. The choice 3 is where the minimum occurs rather than what it is, and 11 is the value at x = 0.
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The graph of y = a(x - 2)^2 + k has vertex (2, 3) and passes through (0, 7). What is the value of a?
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Answer: 1
The vertex gives k = 3. Substituting the point: 7 = a(0 - 2)^2 + 3 = 4a + 3, so 4a = 4 and a = 1. Forgetting to square the -2 gives a = 2.
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